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Acceleration

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Question

A body is projected horizontally from a height of 78.4m with a velocity 10 M/s. Its velocity after 3seconds is ? (G=10m/S2)(take the direction of projection on i vector and vertically upward direction on J vector)

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Solution

Velocity after 3 seconds:
v⃗ =u⃗ +a⃗ t
=u⃗ +g⃗ t
=10iˆ+10(−j)(3)
=(10iˆ−30j) m/s

so velocity =√(10^2+30^2)
=√100+900 =√1000
=31.622 m/s

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