Question

A body is projected horizontally from the top of a hill with a velocity of $9.8m/s$. What time elapses before the vertical velocity is twice the horizontal velocity?

• A. $0.5sec$
• B. $1sec$
• C. $2sec$
• D. $1.5sec$

Answer 1

The correct option is C $2sec$

$u_v=0$
$v=9.8\times 2=19.6$ $m/s$
$a=-9.8m/s^2$
$v=u+at$
$\frac{19.6}{9.8}=t\Rightarrow t=2$ sec