A body is projected horizontally from the top of a tower with an initial velocity of 18ms−1. It hits the ground at an angle of 45∘ with horizontal. What is the vertical component of velocity when the body strikes the ground?
A
9m/s
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B
9√2m/s
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C
18m/s
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D
18√2m/s
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Solution
The correct option is C18m/s Let v be the velocity with which body strikes the ground.
Horizontal component of velocity doesn’t change during the motion. ∴vcos45∘=u=18m/s⇒v=18√2m/s
Vertical component when it strikes the ground =vsin45∘=18√2×1√2=18m/s