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Question

A body is projected horizontally from the top of a tower with an initial velocity of 18 ms1. It hits the ground at an angle of 45 with horizontal. What is the vertical component of velocity when the body strikes the ground?

A
9 m/s
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B
92 m/s
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C
18 m/s
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D
182 m/s
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Solution

The correct option is C 18 m/s
Let v be the velocity with which body strikes the ground.
Horizontal component of velocity doesn’t change during the motion.
vcos45=u=18 m/sv=182 m/s

Vertical component when it strikes the ground =vsin45=182×12=18 m/s

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