A body is projected horizontally with a velocity - 23 ms -1 from a height of 5 m- What is the velocity of the body on reaching the ground-

The correct option is B 11 ms ^ 1 Total energy is conserved.Initial energy = 1 2 m× 23+m× 9.8× 5 =11.5m+49m =60.5m Fnal energy = 1 ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Pure Rolling

A body is pro...

Question

A body is projected horizontally with a velocity $\sqrt{23} {m s}^{- 1}$ from a height of $5$ m. What is the velocity of the body on reaching the ground?

22 {m s}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11 {m s}^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

62 {m s}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 {m s}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $11 {m s}^{- 1}$
Total energy is conserved.
Initial energy $= \frac{1}{2} m \times 23 + m \times 9.8 \times 5 = 11.5 m + 49 m = 60.5 m$
Fnal energy $= \frac{1}{2} m v^{2} \frac{1}{2} m v^{2} = 60.5 m v^{2} = 121 m^{2} / s^{2} v = 11 m / s$

Suggest Corrections

Similar questions

Q. A body, projected vertically up with a velocity of

20 m s^{- 1}

, reaches a height of

20 m

. If it is projected with a velocity of

40 m s^{- 1}

, then the maximum height reached by the body is:

Q. A body projected vertically up with a velocity of 10 m s

^{- 1}

reaches a height of 20 m. If it is projected with a velocity of 20 m s

^{- 1}

, then the maximum height reached by the body is :

Q. A body of mass

m

is projected horizontally with a velocity

v

from the top of a tower of height

h

and it reaches the ground at a distance

x

from the foot of the tower. If a second body of mass

2 m

is projected horizontally from the top of a tower of height

2 h

, it reaches the ground at a distance

2 x

from the foot of the tower. The horizontal velocity of the second body is

A body is projected from the ground with the velocity of $10 {m s}^{- 1}$ such that it makes an angle of $30o\displaystyle { 30 }^{ o }$ with the horizontal. What is the horizontal velocity at the maximum height?

Q. A body is projected with an initial velocity of 50

m s^{- 1}

at angle 53 with the horizontal. Calculate the velocity when it reaches a height of 40 m.

Join BYJU'S Learning Program

A body is projected horizontally with a velocity √23 ms−1 from a height of 5 m. What is the velocity of the body on reaching the ground?

The correct option is B 11 ms−1Total energy is conserved.Initial energy =12m×23+m×9.8×5=11.5m+49m=60.5mFnal energy =12mv212mv2=60.5mv2=121m2/s2v=11m/s

A body is projected horizontally with a velocity $\sqrt{23} {m s}^{- 1}$ from a height of $5$ m. What is the velocity of the body on reaching the ground?

The correct option is B $11 {m s}^{- 1}$
Total energy is conserved.
Initial energy $= \frac{1}{2} m \times 23 + m \times 9.8 \times 5 = 11.5 m + 49 m = 60.5 m$
Fnal energy $= \frac{1}{2} m v^{2} \frac{1}{2} m v^{2} = 60.5 m v^{2} = 121 m^{2} / s^{2} v = 11 m / s$