Question

A body is projected up a $45^o$ rough inclined plane. If the coefficient of friction is 0.5, then the retardation of the block is

• A. $\frac{g}{2\sqrt{2}}$
• B. $\frac{g}{\sqrt{2}}$
• C. $\frac{3g}{2\sqrt{2}}$
• D. $\frac{g}{2}$

Answer 1

The correct option is C $\frac{3g}{2\sqrt{2}}$

Retardation on an inclined plane
$=\mu g\cos \theta +g$ $sin\theta$=$0.5\times g\times \frac{1}{\sqrt{2}}+g\frac{1}{\sqrt{2}}=\frac{3g}{2\sqrt{2}}$