A body is projected upward with a velocity u. It passes through a certain point above the ground after t1. From this instant, the time after which the body passes through the same point during the return journey is
Suppose v be the velocity attained by the body after time t1. Then
v = u - g t1 .. (i)
Let the body reache the same points at time t2. Now velocity will be downward with same magnitude v ,
then
- v = u - g t2 .. (ii)
or t2 - t1 = 2vg = 2g (u - g t1) = 2 ( ug - t1)