1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body is projected vertically from the surface of the earth of radius R with a velocity equal to half of the escape velocity. The maximum height reached by the body is:

A
R2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
R3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
R4
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
R5
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

The correct option is B R3 According to the law of conservation of energy:Total energy of the body on the surface of earth = Total energy of the body at a height ‘h’ reached by it⇒(P.E+K.E)Surface=(P.E+K.E)Max Height⇒−GMmR+12m(Ve2)2=−GMmR+h+12m(0)2 ........ (1)We know that: Ve=√2GMR ..........(2)Sunstituting (2) in (1) and solving, we get h=R3

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Acceleration Due to Gravity
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program