Question

# A body is projected vertically up with u. Its velocity at half its maximum height is?

A
u2
B
u22
C
2u
D
u2

Solution

## The correct option is D $$\displaystyle\frac{u}{\sqrt{2}}$$For a body projected up,$${ H }_{ max }=\cfrac { { u }^{ 2 } }{ 2g }$$By equation$${ v }^{ 2 }={ u }^{ 2 }-2gh$$Putting, $$h=\cfrac { { H }_{ max } }{ 2 } =\cfrac { { u }^{ 2 } }{ 4g }$$$${ v }^{ 2 }={ u }^{ 2 }-2g{ v }^{ 2 }={ u }^{ 2 }-2g\cfrac { { u }^{ 2 } }{ 4g }$$$$={ u }^{ 2 }-\cfrac { { u }^{ 2 } }{ 2 }$$$${ v }^{ 2 }=\cfrac { { u }^{ 2 } }{ 2 }$$$$v=\cfrac { u }{ \sqrt { 2 } }$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More