A body is projected vertically upward with speed $10 m / s$ and other at same time with same speed in downward direction form the top of a tower. The magnitude of acceleration of first body with respect to second is {take $g = 10 m / s^{2}$ }

Zero

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5 m / s^{2}

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10 m / s^{2}

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20 m / s^{2}

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Solution

The correct option is A Zero
The magnitude of acceleration is taken place with $g$ and second body has a downward acceleration with respective of $g .$
This denotes first body and utilize with same acceleration and no one is accelerating with respect to another $.$
The magnitude of acceleration is zero because there is no change in velocity by practical $.$ it is ultimately $0$ by perfect measurement $.$
Hence,
option $(A)$ is correct answer.

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A body is projected vertically upward with speed 10 m/s and other at same time with same speed in downward direction form the top of a tower. The magnitude of acceleration of first body with respect to second is {take g=10m/s2}

A body is projected vertically upward with speed $10 m / s$ and other at same time with same speed in downward direction form the top of a tower. The magnitude of acceleration of first body with respect to second is {take $g = 10 m / s^{2}$ }