Question

A body is projected,vertically upwards,with a certain velocity.It just reaches a point 10 m.What was the velocity of projection .$g=9.8\frac{m}{s^2}.$

Answer 1

Step 1: Given that ,

Final velocity (v)=0.

Distance (S) =10 m.

Acceleration a= - g and $g=9.8\frac{m}{s^2}.$

Step 2: Formula

$v^2-u^2=2as.$

Step 3:Calculation.

The velocity with which it is thrown is $v^2-u^2=2as.$

$$\begin{gathered} 0-u^2=2(-9.8)\left(10\right). \\ {u}^2=196. \\ u=\sqrt{196.} \\ u=14\frac{m}{s}. \end{gathered}$$

Step 4:

Hence, the velocity with which it is thrown is $u=14\frac{m}{s}.$