Question

A body is projected vertically upwards with a velocity of $10{ms}^{-1}$ and another body is projected simultaneously from the same point with a velocity of $20{ms}^{-1}$ at an angle of $\frac{\pi }{6}$ with the horizontal. The distance between the two bodies after one second from the time of projection is (Acceleration due to gravity is $10{ms}^{-2}$)

• A. $10m$
• B. $10\sqrt{3}m$
• C. $20m$
• D. $20\sqrt{3}m$

Answer 1

Answer: (B)

$10\sqrt{3}m$

Vertical velocity of the second body is: $20sin\frac{\pi }{6}=10m/s$

which is same as the first body, thus, the two bodies are always at the same height.

Horizontal velocity of the second body is: $20cos\frac{\pi }{6}=10\sqrt{3}m/s$

After one second the distance between the bodies is $10\sqrt{3}m$.