A body is projected vertically upwards with a velocity of $96 f t s^{- 1}$ . How long will the body remain in air? $(g = 32 f t s^{- 2})$

3 s

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6 s

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9 s

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12 s

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Solution

The correct option is B $6 s$
A body is projected vertically upwards with a velocity of $96 f t / s$ .
$t = \frac{v}{a} = \frac{96}{32} = 3 s$
since the body was thrown in the air and also it comes down Time is $2 t = 2 * 3 = 6 s$

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