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Question

A body is projected with a speed of 40m/s vertically up from the ground. What is the maximum height reached by the body? What is the entire time of motion? What is the velocity at 5sec after the projection? Take g=10m/s2.

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Solution

u=40m/s
At maximum height, v=0
u22aHmax=0
Hmax=u22g=40×402×10
Hmax=80m
ugt=0
t=ug
Entire time of motion =2ug=2×4010=8s
v=ugt
=4010×5
v=10m/s
v5s=10(^j)m/s

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