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Standard XII

Physics

General Gravity Problem

A body is pro...

Question

A body is projected with a speed of $40 m / s$ vertically up from the ground. What is the maximum height reached by the body? What is the entire time of motion? What is the velocity at $5 s e c$ after the projection? Take $g = 10 m / s^{2}$ .

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Solution

$u = 40 m / s$
At maximum height, $v = 0$
$u^{2} - 2 a H_{m a x} = 0$
$H_{m a x} = \frac{u^{2}}{2 g} = \frac{40 \times 40}{2 \times 10}$
$H_{m a x} = 80 m$
$u - g t = 0$
$t = \frac{u}{g}$
Entire time of motion $= \frac{2 u}{g} = 2 \times \frac{40}{10} = 8 s$
$v = u - g t$
$= 40 - 10 \times 5$
$v = - 10 m / s$
$_{5 s} = 10 (^- j) m / s$

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A body is projected with a speed of 40m/s vertically up from the ground. What is the maximum height reached by the body? What is the entire time of motion? What is the velocity at 5sec after the projection? Take g=10m/s2.

u=40m/sAt maximum height, v=0u2−2aHmax=0Hmax=u22g=40×402×10Hmax=80mu−gt=0t=ugEntire time of motion =2ug=2×4010=8sv=u−gt=40−10×5v=−10m/s−→v5s=10(^−j)m/s

A body is projected with a speed of $40 m / s$ vertically up from the ground. What is the maximum height reached by the body? What is the entire time of motion? What is the velocity at $5 s e c$ after the projection? Take $g = 10 m / s^{2}$ .