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Question

A body is projected with a velocity of 30 m/s at an angle of 60 to the horizontal. Find the magnitude of velocity when the angle between the velocity vector and acceleration vector is 120.

A
203 m/s
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B
203 m/s
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C
103 m/s
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D
103 m/s
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Solution

The correct option is C 103 m/s
Let the final velocity be V when the angle between velocity vector and acceleration vector is 120.
Only acceleration acting on the body will be acceleration due to gravity in downward direction as shown in figure.

Hence angle made by velocity vector with horizontal, ϕ=12090=30
Since there is no acceleration in horizontal direction, therefore horizontal velocity remains same during the projectile.
uxcos60=Vcosϕ
30cos60=Vcos30
15=V×32
V=103 m/s

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