A body is projected with an initial velocity of $20^i + 20^j$ . It clears a wall at a distance of 20 m. Find the velocity when it clears the wall.

20i + 10j

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20i – 10j

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15i + 10j

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20i + 15j

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Solution

The correct option is A 20i + 10j
Let t be the time of crossing. Then,
$u c o s θ \times t = 20 \Rightarrow t = 1 s V_{y} = u_{y} - g t = 20 - 10 (1) = 10 m s^{- 1} ∴ \to v = 20^i + 10^j$

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