Question

A body is projected with an initial velocity of 50 $m{s}^{-1}$ at angle 53 with the horizontal. Calculate the velocity when it reaches a height of 40 m.

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$V_x=ucos\theta =5cos{53}^0=30m{s}^{-1}{v}_y^2=u_y^2-2gh={\left(50sin{53}^0\right)}^2-2\times 10\times 40V_y=\pm 20\sqrt{2}m{s}^{-1}\therefore v=30\hat{i}\pm 20\sqrt{2}\hat{j}m{s}^{-1}$