Question

A body is projected with u =19.6m/s find the max height and time of flight

Answer 1

u = 19.6 m/s

at highest point v =0

using v= u - gt

0 =19.6 - 9.8 * t

t = 19.6/9.8= 2sec (time to reach max height)

now using v^2 = u^2 - 2gh

0 = (19.6)^2 - 2* 9.8 * h

h = 19.6*19.6/2*9.8

h = 19.6 m

Ans. t = 2 sec, h = 19.6m