A body is released from the top of a tower. The body covers a distance of $24.5 m$ in the last second of its motion. The height of tower is

59.8 m

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44.1 m

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39.2 m

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49 m

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Solution

The correct option is B $44.1 m$
$\sqrt{2 g h} = \sqrt{2 g (h - 24.5)} + 1 \Rightarrow \sqrt{2 h} - \sqrt{g} = \sqrt{2 (h - 24.5)} \Rightarrow \sqrt{2 g h} = \frac{g + 49}{2} \Rightarrow h = 44.13$

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A body is released from the top of a tower. The body covers a distance of 24.5m in the last second of its motion. The height of tower is

The correct option is B 44.1m√2gh=√2g(h−24.5)+1⇒√2h−√g=√2(h−24.5)⇒√2gh=g+492⇒h=44.13

A body is released from the top of a tower. The body covers a distance of $24.5 m$ in the last second of its motion. The height of tower is

The correct option is B $44.1 m$
$\sqrt{2 g h} = \sqrt{2 g (h - 24.5)} + 1 \Rightarrow \sqrt{2 h} - \sqrt{g} = \sqrt{2 (h - 24.5)} \Rightarrow \sqrt{2 g h} = \frac{g + 49}{2} \Rightarrow h = 44.13$