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Law of Conservation of Mechanical Energy

A body is rot...

Question

A body is rotated in the vertical plane by means of thread of length $ℓ = 4$ m with minimum possible speed. At the highest point B the thread breaks and the body moves under gravity and strikes at C. What is the horizontal range AC (in m)?

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Solution

$a t t h e t i m e o f b r e a k o f f v e l o c i t i s \sqrt{g l} . T i m e t a k e n t o r e a c h g r o u n d t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{4 l}{g}} R a n g e = \sqrt{g l} \times \sqrt{\frac{4 l}{g}} = \sqrt{4 l^{2}} = 8$

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