Question

A body is rotating with angular momentum L. If I is its moment of inertia about the axis of rotation, its kinetic energy of rotation is?

• A. $\frac{1}{2}I{L}^2$
• B. $\frac{1}{2}IL$
• C. $\frac{1}{2}\left(I^2/L\right)$
• D. $\frac{1}{2}\cdot \frac{L^2}{I}$

Answer 1

The correct option is A $\frac{1}{2}I{L}^2$

As we know linear Kinetic energy $=\frac{1}{2}m{v}^2$ where m= mass and v= velocity.

Similarly rotational kinetic energy is given by $=\frac{1}{2}I{L}^2$ where I- moment of inertia and L=angular momentum