Question

A body is sliding down an inclined plane (angle of inclination ${45}^o$). If the coefficient of friction is $0.5$ and $g=9.8m/s^2$, then the downward acceleration of the body in $m/s^2$ is:

• A. $\frac{4.9}{\sqrt{2}}$
• B. $4.9\sqrt{2}$
• C. $19.2\sqrt{2}$
• D. $4.9$

Answer 1

The correct option is A $\frac{4.9}{\sqrt{2}}$

$F=mgsin\theta -\mu mgcos\theta =ma$

$a=\frac{g}{\sqrt{2}}-0.5g\frac{1}{\sqrt{2}}$

$a=\frac{4.9}{\sqrt{2}}$