A body is submerged in water. It is taken out and then submerged in mercury. What happens to its relative density with respect to the liquid in which it is submerged?

increases

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decreases

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remains constant

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can't say

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Solution

The correct option is B decreases
Relative density of a substance 1 with respect to some other substance 2 is
$ρ_{r} = \frac{ρ_{1}}{ρ_{2}}$
Since the density of mercury is greater than that of water, the relative density of body with respect to mercury is lesser than that in water.

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If an object is submerged in water, then taken out and submerged in mercury. Then which of the following will be true?

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A body is submerged in water. It is taken out and then submerged in mercury. What happens to its relative density with respect to the liquid in which it is submerged?

The correct option is B decreasesRelative density of a substance 1 with respect to some other substance 2 is ρr=ρ1ρ2Since the density of mercury is greater than that of water, the relative density of body with respect to mercury is lesser than that in water.

The correct option is B decreases
Relative density of a substance 1 with respect to some other substance 2 is
$ρ_{r} = \frac{ρ_{1}}{ρ_{2}}$
Since the density of mercury is greater than that of water, the relative density of body with respect to mercury is lesser than that in water.