You visited us 1 times! Enjoying our articles? Unlock Full Access!

Variation of G Due to Height and Depth

A body is sus...

Question

A body is suspended from a spring balance kept in a satellite. The reading of the balance is $W_{1}$ , when the satellite goes in an orbit of radius $R$ and is $W_{2}$ , when it goes in an orbit of radius $2 R$ .

W_{1} = W_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

W_{1} < W_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

W_{1} > W_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

W_{1} \neq W_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $W_{1} = W_{2}$
For a body revolving around the earth at any orbital radius, the gravitational force towards earth is countered by centrifugal force as shown in figure.
i.e. $F_{g} = F_{v}$
So, for a body hanging in the satellite, $W_{1} + F_{v} = F_{g} \Rightarrow W_{1} = 0$
Similarly, $W_{2} = 0$ . Thus $W_{1} = W_{2}$ .

Suggest Corrections

Similar questions

W_{1} \neq W_{2}

W_{1}

W_{2}

W_{1}

R

W_{2}

2 R .

W_{1}

W_{2}

W_{1}

W_{2}

W_{3}

W_{4}

Join BYJU'S Learning Program