Question

A body is thrown horizontally with a velocity $\sqrt{2gh}$ from the top of a tower of height $h$. It strikes the level ground through the foot of the tower at a distance $x$ from the tower. The value of $x$ is

• A. $h$
• B. $h/2$
• C. $2h$
• D. $2h/3$

Answer 1

The correct option is C $2h$

Given Horizontal velocity $=V_H=\sqrt{2gh}$,

Vertical velocity$=V_V=0$

Using $s=ut+\frac{1}{2}a{t}^2$

$\Rightarrow -h=0-\frac{1}{2}g{t}^2$ $\Rightarrow t=\sqrt{\frac{2h}{g}}$

$\therefore$ $x=V_H\times t$ $\Rightarrow x=\sqrt{2gh}\times \sqrt{\frac{2h}{g}}=2h$