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Question

A body is thrown up with an initial velocity of 10 m s1. It reaches a maximum height, h. Find the value of h. [Take acceleration due to gravity, g=10 m s2]


A

10 m

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B

15 m

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C

5 m

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D

20 m

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Solution

The correct option is C

5 m


Given,
initial velocity, u=10 m s1
Using equation,
v2 = u2+2as
Here, a=g [ acceleration due to gravity is acting opposite to the direction of motion]
s=h
At highest point,
Final velocity, v=0
0=u22gh
h=u22g
=10×102×10=5 m


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