A body is thrown up with an initial velocity of 10 m s−1. It reaches a maximum height, h. Find the value of h. [Take acceleration due to gravity, g=10 m s−2]
5 m
Given,
initial velocity, u=10 m s−1
Using equation,
v2 = u2+2as
Here, a=−g [∵ acceleration due to gravity is acting opposite to the direction of motion]
s=h
At highest point,
Final velocity, v=0
⇒0=u2−2gh
⇒h=u22g
=10×102×10=5 m