A body is thrown vertically upwards with velocity u. The greatest height h to which it will rise is;

u/2g

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u/g

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u² /g

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u² /2g

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Solution

The correct option is D
u² /2g

Initial velocity = u m/s, final velocity = 0 , acceleration = - g

Let 'h' be the maximum height. Thus, applying kinematic equation, we get

v² - u² = 2 a h

or, 0 - u² = 2 (-g) h

or, h = u² / 2g

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