wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body is thrown with the velocity v0 at an angle of θ to the horizon. Determine v0 in ms1 if the maximum height attained by the body is 5 m and at the highest point of its trajectory the radius of curvature is r=3m. Neglect air resistance. [Use 80 as 9].

Open in App
Solution

Radius of curvature at the highest point
r=vgr=(v0cosθ)2g
v0cosθ=gr....(i)
Maximum height h=v20sin2θgv0sinθ=gh....(ii)
By using (i) and (ii), we get
v20sin2θ+v20cos2θ=gh+gr=g(h+r)
v0=g(h+r)=10(5+3)=9 ms1.
1554589_986331_ans_62e6426791c94e4faeaa1cf630eec910.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon