Question

A body loses half of its velocity on penetrating $6cm$ in a wooden block. How much will it penetrate more before coming to rest?

• A. $1cm$
• B. $2cm$
• C. $3cm$
• D. $4cm$

Answer 1

The correct option is B $2cm$

$v^2-u^2=2as$

$(\frac{v}{2}{)}^2-v^2=2a6=-\frac{3v^2}{4}$

$a=\frac{v^2}{16}$

$0-(\frac{v}{2}{)}^2=2as$

$\frac{v^2}{4}=2\frac{v^2}{16}s$

$s=2cm$