A body mass 8 kg placed on a smooth horizontal table is connected by a light string passing over a pulley to a hanging body of mass 2 kg. Find the acceleration of the masses and the tension in the string. $(g = 10 m / s^{2})$ .

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Solution

Let the tension be T and acceleration be a. Then,
From FBD of block of mass $8 K g$
$T = 8 a$ ..... eq.1
And, From FBD of block of mass $2 K g$
$2 g - T = 2 a$
$\Rightarrow T = 20 - 2 a = 8 a$ from eq.1
$\Rightarrow a = 2 m / s^{2}$
$\Rightarrow T = 8 a = 16 N$

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A body mass 8 kg placed on a smooth horizontal table is connected by a light string passing over a pulley to a hanging body of mass 2 kg. Find the acceleration of the masses and the tension in the string. (g=10m/s2).

Let the tension be T and acceleration be a. Then,From FBD of block of mass 8Kg T=8a ..... eq.1And, From FBD of block of mass 2Kg 2g−T=2a⇒T=20−2a=8a from eq.1⇒a=2m/s2⇒T=8a=16N

A body mass 8 kg placed on a smooth horizontal table is connected by a light string passing over a pulley to a hanging body of mass 2 kg. Find the acceleration of the masses and the tension in the string. $(g = 10 m / s^{2})$ .

Let the tension be T and acceleration be a. Then,
From FBD of block of mass $8 K g$
$T = 8 a$ ..... eq.1
And, From FBD of block of mass $2 K g$
$2 g - T = 2 a$
$\Rightarrow T = 20 - 2 a = 8 a$ from eq.1
$\Rightarrow a = 2 m / s^{2}$
$\Rightarrow T = 8 a = 16 N$