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Standard IX

Physics

Types of Work

A body moves ...

Question

A body moves a distance of $20 m$ along a straight line under the action of a force of $10 N$ . If the work done is $100 J$ , the angle between force and displacement vectors i:

0^{o}

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30^{o}

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45^{o}

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60^{o}

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Solution

The correct option is D $60^{o}$
$W = F . s =$ $F \times s c o s θ$
$100 = 10 \times 20 c o s θ$
$θ = 60^{0}$

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A body moves a distance of 20 m along a straight line under the action of a force of 10 N. If the work done is 100 J, the angle between force and displacement vectors i:

The correct option is D 60oW=F.s=F×scosθ100=10×20cosθθ=600

A body moves a distance of $20 m$ along a straight line under the action of a force of $10 N$ . If the work done is $100 J$ , the angle between force and displacement vectors i:

The correct option is D $60^{o}$
$W = F . s =$ $F \times s c o s θ$
$100 = 10 \times 20 c o s θ$
$θ = 60^{0}$