Question

A body moves according to the formula$v=1+t^2$ where $v$ is the velocity at time $t$. The acceleration after $3sec$ will be ($vincm/sec$)

• A. $24cm/se{c}^2$
• B. $12cm/se{c}^2$
• C. $6cm/se{c}^2$
• D. None of these

Answer 1

The correct option is C

$6cm/se{c}^2$

Step 1. Given data

Velocity is $v=1+t^2$ where$t$ is time

Step 2. Finding acceleration

Acceleration is given by

$$\begin{gathered} a=\frac{dv}{dt}=\frac{d(1+t^2)}{dt} \\ =2t \end{gathered}$$

At $t=3sec$ acceleration will be

$a=2\times 3=6cm/s^2$

Hence, option C is correct.