Question

A body moves along a circular path of radius $5m$. The coefficient of friction between the surface of the path and body is $0.5$. The angular velocity, in $rad{s}^{-1}$ with which the body should move so that it does not leave the path is ($g=10m/s^2$):

• A. $4$
• B. $3$
• C. $2$
• D. $1$

Answer 1

Answer: (D)

$1$

Here, Centripetal force $=$ Frictional force
$mr{\omega }^2=\mu mg$

$\therefore {\omega }^2=\frac{\mu g}{r}$

$\therefore {\omega }^2=\frac{0.5\times 10}{5}=1$

$\therefore \omega =1rad/s$