A body moves for a total of nine second starting from rest with uniform acceleration and then with uniform retardation, which is twice the value of acceleration and then stops. The duration of uniform acceleration
A
3s
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B
4.5s
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C
5s
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D
6s
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Solution
The correct option is D3s Consider the acceleration of the is α and retardation is β
and according to question retardation is twice that acceleration then
β=2a
Body moves with acceleration α for t1 sec
v=u+at
v=0+αt1.....(1)
Body retards with 2α for time t2 sec and then body becomes rest .
v=u+at
Here,
u=αt1v=0a=−2α
0=αt1−2αt2t1=2t2
As
t1+t2=9sec
Then,
t1=3sec
t2=6sec
Therefore, 3sec body moves with uniform acceleration.