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Work Energy Theorem Application

A body moves ...

Question

A body moves from point A and B under the action of a force, varying in magnitude as shown in figure below. Obtain the work done. Force is expressed in newton and displacement is in metre.

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Solution

Work done=Area enclosed from A to B
=Area enclosed from A to L(Since area from L to M and M to B are equal and opposite polarity)
$= 10 \times 2 + \frac{1}{2} \times 1.5$
$= 20 + 2.5 = 22.5 J$

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