Question

A body moves from rest with a uniform acceleration and travels 270 m in 3 s.Find the velocity of the body at 10 s after the start.

Answer 1

Here the main thing is uniform acceleration which means that "a" would be constant such that acceleration after 3s would be equal to acceleration after 10 s so from 1st case we will find the acceleration from 2nd equation of motion.
i.e from this equation we will find


here initial speed u=0 so ut = 0

a = 60 - (1)
Now we know that v= u+at
from eqn 1 a= 60
so here v= 0+ 6010
v=600m/s