Question

A body moves from rest with uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 s after the start.

• A. $600m{s}^{-1}$
• B. $6m{s}^{-1}$
• C. $60m{s}^{-1}$
• D. $100m{s}^{-1}$

Answer 1

The correct option is A $600m{s}^{-1}$

$u=0,s=270m,t=3s$
$s=ut+\frac{1}{2}a{t}^2$
$270=0\times 3+\frac{1}{2}\times a\times 3^2$
$a=60m/s^2$

Now putting the value of $a$ in $v=u+at$,
Velocity after $t=10s$ is given by
$v=0+60\times 10=600m/s$