Question

A body moves from rest with uniform acceleration and travels $270m$ in $3s$. What will be the velocity of the body at $10s$ after the start?

• A. $500m{s}^{-1}$
• B. $600m{s}^{-1}$
• C. $700m{s}^{-1}$
• D. None of these

Answer 1

Answer: (B)

$600m{s}^{-1}$

$u=0$
$s=270m$
Let accelaration $=a$
or $s=ut+\frac{1}{2}a{t}^2$
or $270=(0\times 3)+(\frac{1}{2}\times a\times 3^2)$
or $a=60m{s}^{-2}$
Now, $t_1=10s$
$\therefore v=u+a{t}_1=0+(60\times 10)=600m{s}^{-1}$