Question

A body moves from rest with uniform accelerations and travels 270 m in 3 sec. Find the velocity of the body 10 sec after that start.

Answer 1

ATQ,

$u=0m/s$

$s=270m$

$t=3s$

(i) $s=ut+\frac{1}{2}a{t}^2$

$\Rightarrow 270=\left(0\right)\left(3\right)+\frac{1}{2}a\left(9\right)$

$\Rightarrow a=60m/s^2$

Now, $v=u+at$ [for $t=10s$}

$=0+\left(60\right)\left(10\right)$

$=600m/s$