A body moves in a vertical semicircle of radius r from the lowest point to highest point. What is the amount of work done? (Assume mass of the body to be 'm' kg and acceleration due to gravity to be $g m s^{- 2}$ )

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Solution

As the body moves in a vertical semicircle from its lowest to the highest point, net displacement is equal to 2r. The only force acting is gravity in vertical direction i.e., the direction of displacement. So total work done = force due to gravity $\times$ net displacement = mg $\times$ 2r = 2mgr.

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A body moves in a vertical semicircle of radius r from the lowest point to highest point. What is the amount of work done? (Assume mass of the body to be 'm' kg and acceleration due to gravity to be g ms−2)

As the body moves in a vertical semicircle from its lowest to the highest point, net displacement is equal to 2r. The only force acting is gravity in vertical direction i.e., the direction of displacement. So total work done = force due to gravity × net displacement = mg × 2r = 2mgr.

A body moves in a vertical semicircle of radius r from the lowest point to highest point. What is the amount of work done? (Assume mass of the body to be 'm' kg and acceleration due to gravity to be $g m s^{- 2}$ )

As the body moves in a vertical semicircle from its lowest to the highest point, net displacement is equal to 2r. The only force acting is gravity in vertical direction i.e., the direction of displacement. So total work done = force due to gravity $\times$ net displacement = mg $\times$ 2r = 2mgr.