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Question

A body moves on a rough horizontal surface with acceleration a when it is subjected to a horizontal force. If the applied force is doubled, it moves with acceleration

A
equal to 2a
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B
less than 2a
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C
greater than 2a
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D
equal to a
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Solution

The correct option is D greater than 2a
Ff=ma1
a1=a which is given
F=f+ma1
Now applied force is doubled therefore
2Ff=ma2
ma2=2(f+ma1)f
This gives ma2=f+ma1+ma1=f+2ma1
Therefore, clearly, a2>2a1
a2>2a

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