A body moves with constant speed $v$ along the circumference of a circle of radius $r$ . If it completes half of the revolution in $t$ seconds, then the magnitude of the average acceleration is :

0

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\frac{2 v}{t}

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\frac{v}{t}

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All the above

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Solution

The correct option is A $\frac{2 v}{t}$
${\to a}_{a v g} = a v g . a c c l^{n} = \frac{{\to v}_{2} - {\to v}_{1}}{t_{2} - t_{1}}$
Initial velocity, $v_{A} = v^i$
Final velocity, ${\to v}_{B} = - v^i$
${\to a}_{a v g} = \frac{- v - (v)}{t} = \frac{- 2 v}{t} o r \frac{2 v}{t}$

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