Question

A body moves with uniform velocity of $u=7m/s$ from $t=0tot=1.5s$. It starts moving with an acceleration of $10m/s^2$. The distance between $t=0tot=3s$ will be:

• A. 47.75 m
• B. 32.25 m
• C. 16.75 m
• D. 27.50 m

Answer 1

The correct option is B 32.25 m

Distance covered in first 1.5 sec $=ut=1.5\times 7=10.5m$
Distance covered in last 1.5 sec $=ut+\frac{1}{2}\times 10\times t^2=1.5\times 7+5\times 2.25=10.5+11.25=21.75m$
Total distance $=10.5+21.75=32.25m$