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Question

A body moving along the positive xaxis with uniform acceleration of 4ms2. Its velocity at x=0 is 10ms1. The time taken by the body to reach a point at x=12cm is:


A
(2s)
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B
(0.25s)
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C
(3s)
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D
(0.0125s)
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Solution

The correct option is D (0.0125s)
Acceleration a=4m/s2
Initial velocity u=10m/s
Distance traveled x=12cm=12×102m
From kinematics, v2u2=2ax
v2=u2+2ax
=100+2×(4)×12×102
=1000.96=99.04
v=9.95m/s
v=u+at
t=vua
=9.95104=0.0125s

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