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Acceleration

A body moving...

Question

A body moving along $X$ direction has at any instant its $x$ ordinate given by $x = a + b t + c t^{2}$ .If the accerlation of particle is $x c$ , find $x$ .

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Solution

$v = \frac{d x}{d t} = b + 2 c t$
Thus, $a = \frac{d v}{d t} = 2 c = x c$ , thus giving $x = 2$

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