MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

First Equation of Motion

A body moving...

Question

A body moving in a straight line with constant retardation"a"loses 3/4 of initial velocity u.what is its time of motion?

A.3u/4

B.3u/4a

C 4u/3

D.4u/3a

Open in App

Solution

v=u+at
here v=u-3/4u=1/4 u
a=-a(retardation)
so
1/4 u = u -at
t=3u/4a (option b)

Suggest Corrections

thumbs-up

15

Similar questions

Q. A body moving with constant retardation 'a' losses

\frac{2}{3}

of its initial velocity

v_{0}

. What is the distance covered by the body in the time during which this occurs?

Q. Velocity of a body moving along a straight line with uniform acceleration

(a)

\frac{3}{4}

of its initial velocity in time

t_{0}

. The total time of motion of the body till its velocity becomes zero is

Q. If a body moves with uniform retardation, the velocity-time graph is a straight line

Q. A particle having initial velocity

10 m/s

is moving with constant acceleration

4 {m/s}^{2}

. The particle is moving in a straight line. Find the distance travelled by the particle in

7^{t h}

second of its motion

Q. A moving body, when given a retardation of

2 m s^{- 2}

25 s

. What was its initial velocity?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

First Equation of Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

First Equation of Motion

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon