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First Equation of Motion

A body moving...

Question

A body moving in a straight line with constant retardation"a"loses 3/4 of initial velocity u.what is its time of motion?

A.3u/4

B.3u/4a

C 4u/3

D.4u/3a

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Solution

v=u+at
here v=u-3/4u=1/4 u
a=-a(retardation)
so
1/4 u = u -at
t=3u/4a (option b)

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