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Question

A body moving in straight line with uniform acceleration crosses at two points A and B with velocities 30 m/s and 60 m/s respectively. The speed of the body when it crosses one third of the distance between A and B after crossing from A is :

A
302 m/s
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B
20/2 m/s
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C
40/2 m/s
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D
25/2 m/s
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Solution

The correct option is A 302 m/s
Given,

u=30m/s velocity at point A

v=60m/s velocity at point B

3rd equation of motion,

2aS=v2u2

2aS=(60)2(30)2

aS=1350. . . .(1)

When the car is at one third of AB,

2aS3=v21(30)2

23aS=v21900

23×1350=v21900 (from 1)

900=v21900

v21=1800

v1=302m/s

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