Question

A body moving with a constant acceleration travels the distances 3 m and 8 m respectively in 1 s and 2 s. Calculate the acceleration of body.

• A. $2m{s}^{-2}$
• B. $-3m{s}^{-2}$
• C. $1m{s}^{-2}$
• D. $-1m{s}^{-2}$

Answer 1

The correct option is A $2m{s}^{-2}$

The distance traveled by the body is given as $s=ut+\frac{1}{2}a{t}^2$.
In this case,
For a distance s= 3 m and time t=1 second, the equation is given as
$3=u\times 1+\frac{1}{2}\times a\times 1^2$

$3=u+0.5a..........\left(i\right)$

For a distance s= 8 m and time t=2 seconds, the equation is given as
$8=u\times 2+\frac{1}{2}\times a\times 2^2$

$8=2u+2a...........\left(ii\right)$

Solving equations (i) and (ii), we get $u=2m/s$ and $a=2m/s^2$.