A body, moving with a constant velocity of $10 m / s$ for 2 seconds, has a displacement of 'A' metres. Afterward, it accelerates at $10 m / s^{2}$ for 2 seconds covering a displacement of 'B' metres. The ratio of B: A is

4 : 3

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5 : 1

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2 : 1

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1 : 2

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Solution

The correct option is C
2 : 1

For A:

Given Velocity $u$ = $10 m / s$

Time = 2 seconds

Displacement $A$ = $u \times t$ = $20 m$

For B:

Displacement $B$ = $u t + \frac{1}{2} \times a \times t^{2}$

$= 10 \times 2 + \frac{1}{2} \times 10 \times 2^{2}$

$= 40 m$

Ratio B : A = 2 : 1

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A body, moving with a constant velocity of 10m/s for 2 seconds, has a displacement of 'A' metres. Afterward, it accelerates at 10m/s2 for 2 seconds covering a displacement of 'B' metres. The ratio of B: A is

The correct option is C 2 : 1 For A: Given Velocity u = 10m/s Time = 2 seconds Displacement A = u×t = 20 m For B: Displacement B = ut+12×a×t2 =10×2+12×10×22 =40 m Ratio B : A = 2 : 1

A body, moving with a constant velocity of $10 m / s$ for 2 seconds, has a displacement of 'A' metres. Afterward, it accelerates at $10 m / s^{2}$ for 2 seconds covering a displacement of 'B' metres. The ratio of B: A is

The correct option is C
2 : 1

For A:

Given Velocity $u$ = $10 m / s$

Time = 2 seconds

Displacement $A$ = $u \times t$ = $20 m$

For B:

Displacement $B$ = $u t + \frac{1}{2} \times a \times t^{2}$

$= 10 \times 2 + \frac{1}{2} \times 10 \times 2^{2}$

$= 40 m$

Ratio B : A = 2 : 1