A body moving with uniform acceleration 8 ms−2 starts from rest. The distance covered by it in fifth second will be
Given that,
The acceleration a=8m/s2
Initial velocity u=0m/s
We know that,
The displacement in the nth second
=u+a(n−12)
Now, the displacement in 5th second
=0+8(5−12)
=36m
Hence, the distance covered by it in fifth second is 36 m